Question

The reaction $Pb{(N{O_3})_2} + 2NaI \to 2NaN{O_3} + Pb{I_2} \downarrow$ is classified as
A.Combination reaction
B.Decomposition reaction
C.Single replacement reaction
D.Double replacement reaction

Answer 1

In chemistry, there are several ways a reaction proceeds, it may be a combination reaction where two-components react to form another, there may be a decomposition reaction where compound may be decomposed, etc.

Complete step by step solution: In the reaction provided in the question, we are provided that one molecule of lead nitrate is reacted with two molecules of sodium iodide which leads to the formation of two molecules of sodium nitrate and one molecule of lead iodide. Now as the reaction takes place we can observe normally that the place of lead is occupied by the sodium atom and on the other hand position of a sodium atom is replaced with the lead atom. This happens because of the reactivity series of metal as sodium possesses a higher position in the reactivity series of metal than the lead atom it is more reactive therefore, it replaces its place and in turn lead occupies sodium’s place. So, therefore, the double displacement occurs in this reaction.

Additional information:
The reason for composing a fair synthetic condition is to clarify the happening reactants (beginning material) and items (outcome). The proportions in which they answer so you can quantify the measure of reactants you need and the measure of merchandise you can make. A skeleton condition is a point at which every item that participates in the response is composed with the substance recipes portraying the synthetic response. Models: The term condition: oxygen + methane. Dioxide with carbon + Fume.

Note: A synthetic response is normally trailed by physical signs that are promptly identified, for example, warmth and light outflow, hasten arrangement, gas advancement, or a difference in appearance, etc.