Question

The reaction $Pb \left( NO _3\right)_2$ and $NaCl$ in water produces a precipitate that dissolves upon the addition of $HCl$ of appropriate concentration The dissolution of the precipitate is due to the formation of

• A. $PbCl _2$
• B. $PbCl _4$
• C. $\left[ PbCl _4\right]^{2-}$
• D. $\left[ PbCl _6\right]^{2-}$

Answer 1

Answer: (C)

$\left[ PbCl _4\right]^{2-}$

Answer 2

When lead ions (Pb2+) react with chloride ions (Cl−), a white precipitate of lead(II) chloride (PbCl2​) forms.
This precipitate is soluble in concentrated hydrochloric acid due to formation of tetrachloroplumbate (II) ion

So the correct answer option is (C)