Question
Inorganic Chemistry Question on Theories of bonding
The reaction of XeF2 with HN(SO2F)2 at 273 K in CF2Cl2 solvent yields
A
XeF4 + SO2 + NH3
B
Xe + SO2 + N2+ HF
C
SOF2+ XeO2 + NH3
D
FXEN(SO2F)2 + HF
Answer
FXEN(SO2F)2 + HF
Explanation
Solution
The correct option is (D) : FXEN(SO2F)2 + HF.