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Chemistry Question on Alkenes

The reaction of propene with HBrHBr in peroxide proceeds through the intermediate

A

H3C−C∙−CH3H_3C - \underset{ \bullet} {C} - CH_3

B

H3C−C∙−CH2BrH_3C - \underset{\bullet}{C} - CH_2 Br

C

H3C−CHBr∣−C∙H2H_3C - \overset{\underset{|}{Br}}{CH} - \overset{\bullet}{C}H_2

D

H3C−CH2−C∙H2 H_3C - CH_2 - \overset{ \bullet}{ C} H_2

Answer

H3C−C∙−CH2BrH_3C - \underset{\bullet}{C} - CH_2 Br

Explanation

Solution

The intermediate produce in case of addition of HBrHBr occurs according to antimarkonicov's rule. Thus we get

CH3−C∙H−CH2BrCH _{3}- \overset{\bullet}{C}H - CH _{2} Br as intermidiate.