The reaction of one equivalent of HBr with CH2=CH–CºCH gives... | CHEMISTRY - ALKENES | SolveeIt | Solveeit

Today, August 18

Question

The reaction of one equivalent of HBr with CH2=CH–CºCH gives :

A

CH2=CH–CºCBr

B

CH2=CH– $\underset{|}{C} = CH_{2}㫺B㫺r$

C

CH3– $\underset{|}{C}HᓽBᓽr$ –CºCH

D

CH2=CH–CH=CHBr

Answer

CH2=CH– $\underset{|}{C} = CH_{2}㫺B㫺r$

Explanation

Solution

When double bond and triple bond is in the conjugation then triple bond is more reactive due to more stable carbocation.

$\longleftrightarrow$

more stable