Question

The reaction of aqueous $KMnO_4$ with $H_2O_2$ in acidic conditions gives

• A. $Mn^{4+}$ and $O_2$
• B. $Mn^{2+}$ and $O_2$
• C. $Mn^{2+}$ and $O_3$
• D. $Mn^{4+}$ and $MnO_2$

Answer 1

Answer: (B)

$Mn^{2+}$ and $O_2$

Answer 2

The reaction of aqueous $KMnO_4 \, with \, H_2O_2 \, in$ acidic medium is $3H_2SO_4+2KMnO_4+5H_2O_2 \rightarrow$
\hspace5mm 5O_2+2MnSO_4+8H_2O+K_2SO_4
In the above reaction, $KMnO_4 \, oxidises \, H_2O_2 \, to \, O_2$ and itself $[MnO_4^-]$ gets reduced to $Mn^{2+}$ ion as $MnSO_4.$ Hence, aqueous solution of $KMnO_4.$ with $H_2O_2 \, yields \, Mn^{2+} \, and \, O_2$ in acidic conditions.