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Question

Chemistry Question on Enthalpy change

The reaction in which ΔH>ΔU\Delta H > \Delta U is

A

N2(g)+3H2(g)2NH3(g)N_{2\left(g\right)} + 3H_{2\left(g\right)} \to 2NH_{3(g)}

B

CH4(g)+2O2(g)CO2(g)+2H2O(l)CH_{4\left(g\right) }+ 2O_{2\left(g\right)} \to CO_{2\left(g\right)} + 2H_{2}O_{\left(l\right)}

C

N2(g)+O2(g)2NO(g)N_{2\left(g\right)} + O_{2\left(g\right)} \to 2NO_{\left(g\right)}

D

CaCO3(S)CaO(S)+CO2(g)CaCO_{3\left(S\right)} \to CaO_{\left(S\right)} + CO_{2\left(g\right)}

Answer

CaCO3(S)CaO(S)+CO2(g)CaCO_{3\left(S\right)} \to CaO_{\left(S\right)} + CO_{2\left(g\right)}

Explanation

Solution

CaCo3(s)CaO(s)+Co2(g)CaCo_{3\left(s\right)} \to CaO_{\left(s\right)}+Co_{2\left(g\right)}
Δn=+1\Delta n=+1
ΔH=ΔU+ΔngRT\Delta H=\Delta U+\Delta n_{g}RT
ΔH>ΔU\Delta H>\, \Delta U