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Question

Chemistry Question on Methods of Preparation of Haloalkanes

The reaction, C6H5N2ClCu2Cl2/HClC2H5Cl+N2{{C}_{6}}{{H}_{5}}{{N}_{2}}Cl\xrightarrow{C{{u}_{2}}C{{l}_{2}}/HCl}{{C}_{2}}{{H}_{5}}Cl+{{N}_{2}}\uparrow is called:

A

Sandmeyer reaction.

B

Gattermann reaction

C

Gattermann-Koch reaction

D

Lederrer Mannase reaction

Answer

Sandmeyer reaction.

Explanation

Solution

The correct option is(A): Sandmeyer reaction.

The given reaction, involving the conversion of an aryl diazonium salt (C 6​ H 5​ N 2+​ Cl −) into a halogenated aromatic compound using copper(I) chloride (Cu 2​ Cl 2​) as a catalyst and hydrochloric acid (HCl) as a reagent, is indeed the Sandmeyer reaction.

So, the correct option is: Sandmeyer reaction.