Question

The reactance of a $25\mu F$ capacitor at the ac frequency of 4000 Hz is

• A. $\frac{5}{\pi}$ohm
• B. $\sqrt{\frac{5}{\pi}}$ohm
• C. 10 ohm
• D. $\sqrt{10}$ohm

Answer 1

Answer: (A)

$\frac{5}{\pi}$ohm

Answer 2

$X_{C} = \frac{1}{2\pi\nu C} = \frac{1}{2\pi \times 4000 \times 25 \times 10^{- 6}} = \frac{5}{\pi}\Omega$