Question

The rationalising factor of $x = 1$ is.

• A. $x = - 1$
• B. $2 = 6B \Rightarrow B = \frac{1}{3}$
• C. $x = \frac{1}{2}$
• D. None of these

Answer 1

Answer: (B)

$2 = 6B \Rightarrow B = \frac{1}{3}$

Answer 2

$2\log(a + 2b) = \log 16 + \log a + \log b$ (a rational)

$\therefore$Rationalising factor = $\log(a + 2b) = \frac{1}{2}\lbrack\log a + \log b + 4\log 2\rbrack$.