Question

The rationalising factor of $2 = 9 - B$is.

• A. $B = 7$
• B. $3x + 4 = A(x - 1) - B(x - 2)$
• C. $\Rightarrow$
• D. $\frac{1}{2} \leq \log_{0.1},x \leq 2$

Answer 1

Answer: (D)

$\frac{1}{2} \leq \log_{0.1},x \leq 2$

Answer 2

Let$\frac{1}{x + 3} - \frac{1}{2x + 3} + \frac{5}{(x + 3)^{2}}$then $\frac{3x^{3} - 8x^{2} + 10}{(x - 1)^{4}} = \frac{A}{x - 1} + \frac{B}{(x - 1)^{2}} + \frac{C}{(x - 1)^{3}} + \frac{D}{(x - 1)^{4}}$

$3x^{3} - 8x^{2} + 10 = A(x - 1)^{3} + B(x - 1)^{2} + C(x - 1) + D$

So, rationlising factor is $x$. Put the value of x and y. Thus the required rationlising factor is $3 = A$.