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Question

Question: The ratio of work done by an ideal diatomic gas to the heat supplied by the gas in an isobaric proce...

The ratio of work done by an ideal diatomic gas to the heat supplied by the gas in an isobaric process is –

A

57\frac{5}{7}

B

35\frac{3}{5}

C

27\frac{2}{7}

D

53\frac{5}{3}

Answer

27\frac{2}{7}

Explanation

Solution

ΔW(ΔQ)P=(ΔQ)P(ΔU)P(ΔQ)P=1(ΔU)P(ΔQ)P\frac{\Delta W}{(\Delta Q)_{P}} = \frac{(\Delta Q)_{P} - (\Delta U)_{P}}{(\Delta Q)_{P}} = 1 - \frac{(\Delta U)_{P}}{(\Delta Q)_{P}}

= 1 – 52R72R\frac{\frac{5}{2}R}{\frac{7}{2}R}= 1 – 57=27\frac{5}{7} = \frac{2}{7}