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Question: The ratio of wavelength of first line of Lyman series of doubly ionized lithium atom to that of the ...

The ratio of wavelength of first line of Lyman series of doubly ionized lithium atom to that of the first line of Lyman series of deuterium (1H2) will be

A

4 : 1

B

1 : 4

C

9 : 1

D

1 : 9

Answer

1 : 9

Explanation

Solution

1λ=Rz2(1n121n22)\frac{1}{\lambda} = Rz^{2}\left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right)