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Question: The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform ac...

The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration ‘a’ is 3 : 2. The value of ‘a’ is (g- Acceleration due to gravity on the earth)

A

32g\frac{3}{2}g

B

g3\frac{g}{3}

C

23g\frac{2}{3}g

D

g

Answer

g3\frac{g}{3}

Explanation

Solution

weightof amaninstationaryliftweight of a man in downward moving lift =mgm(g−a)=32∴\frac{\text{weightof amaninstationarylift}}{\text{weight of a man in downward moving lift }} = \frac{mg}{m(g - a)} = \frac{3}{2}\therefore gg−a=32\frac{g}{g - a} = \frac{3}{2} ⇒ 2g=3g−3a2g = 3g - 3a or a=g3a = \frac{g}{3}