Question
Chemistry Question on Chemistry in Everyday Life
The ratio of the velocities of CH4 and O2 molecules, so that they are associated with de-Broglie waves of equal wavelength is:
Answer
Explanation:
According to de-Broglie's equation:λ=hmvWhere, λ= de-Broglie's wavelengthh= Planck's constantm= Mass of the electronv= Velocity of the electronFor CH4, wavelength is given as:λCH4=hmCH4×vCH4For O2, the wavelength is given as:λO2=hmO2×vO2Since, wavelength of CH4 and O2 are equal, i.e. λCH4=λO2Or,hmCH4×vCH4=hmO2×vO2⇒mCH4×vCH4=mO2×vO2⇒vCH4vo2=mO2mCH4Molecular mass of oxygen =32Molecular mass of methane =16∴vCH4vO2=mO2mCH4=3216=2Hence, the correct answer is 2.