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Question: The Ratio of the sum of \({n^{th}}\) term of \(2A.P\)’\(s\) is \(7n + 1:4n + 27\) find the ratio of ...

The Ratio of the sum of nth{n^{th}} term of 2A.P2A.Pss is 7n+1:4n+277n + 1:4n + 27 find the ratio of this mth{m^{th}} term??

Explanation

Solution

The sum of the first n terms can be calculated for an AP, if the first term and the total terms are known, in the above questions based on progression. An arithmetic sequence as a sequence of numbers in which the second number is obtained for every pair of consecutive terms by adding a fixed number to the first one.

Formula used:
The nth{n^{th}} term of arithmetic progression formula,
an=a+(n1)×d{a_n} = a + (n - 1) \times d
Where,
a=a = First term
d=d = Common difference
n=n = number of terms
an={a_n} = nth term
Common difference can be written as, a,a+2d,a+3d,a+4d,................a+(n1)×da,a + 2d,a + 3d,a + 4d,................a + (n - 1) \times d
For an 1st{1^{st}} A.PA.P’s S1=2a1+(n1)d1{S_1} = 2{a_1} + (n - 1){d_1}
For an 2nd{2^{nd}} A.PA.P’s S2=2a2+(n1)d2{S_2} = 2{a_2} + (n - 1){d_2}
Where,
S1,S2{S_1},{S_2} is representing a Sum.

Complete step-by-step answer:
Given by,
Ratio of sum of nn term of 2A.P2A.P’s=(7n+1):(4n+27) = (7n + 1):\left( {4n + 27} \right)
Let as assume the ratio of these 2A.P2A.P’s mth{m^{th}} terms as am:amam:a'm
We know that,
The nth{n^{th}} term of arithmetic progression formula,
an=a+(n1)×d{a_n} = a + (n - 1) \times d
nn is replaced by mm
Substituting the given equation becomes,
\Rightarrow am:am=a+(m1)d:a+(m1)dam:a'm = a + (m - 1)d:a'+(m - 1)d'
On multiplying by 22 to the right side of the equation,
We get,
\Rightarrow am:am=[2a+2(m1)d]:[2a+2(m1)d]am:a'm = [2a + 2(m - 1)d]:[2a' + 2(m - 1)d']
Simplifying the above equation,
Here,
\Rightarrow am:am=[2a+(2m1)1d]:[2a+(2m1)1d]am:a'm = [2a + \\{ (2m - 1) - 1\\} d]:[2a' + \\{ (2m - 1) - 1\\} d']
Substituting the given formula in above equation,
We know that, for second A.PA.P’s
\Rightarrow S1=2a1+(n1)d1{S_1} = 2{a_1} + (n - 1){d_1}
\Rightarrow S2=2a2+(n1)d2{S_2} = 2{a_2} + (n - 1){d_2}
\Rightarrow am:am=S2m1:S2m1am:a'm = {S_2}m - 1:{S_2}'m - 1
Substituting the above formula is applied to the given equation,
We get,
\Rightarrow am:am=am:a'm = [7(2m1)+1]:[4(2m1)+27][7(2m - 1) + 1]:[4(2m - 1) + 27]
On Simplifying,
\Rightarrow am:am=am:a'm = [14m7+1]:[8m4+27][14m - 7 + 1]:[8m - 4 + 27]
\Rightarrow am:am=am:a'm = [14m6]:[8m+23][14m - 6]:[8m + 23]
Hence, thus the ratio of the mth{m^{th}} term of $$2$$$A.Psis’s is [14m - 6]:[8m + 23]$.

Note: A progression is a particular sequence category for which a formula for the nth term can be obtained. The Arithmetic Progression is the most frequently used sequence in arithmetic with formulas that become easy to understand. If the value of common difference d is positive, then the member terms will grow towards positive infinity, and if the value of d is negative, then the member terms will grow towards negative infinity.