Question

The ratio of the speed of the electron in the first Bohr orbit of hydrogen and the speed of light is equal to - (where e, h and c have their usual meanings)

• A. 2phc/e²
• B. e²/2e₀hc
• C. e²h/2pc
• D. None

Answer 1

Answer: (B)

e²/2e₀hc

Answer 2

mvr =$\frac{nh}{2\pi}$ ….(1)

$\frac{kZe^{2}}{r^{2}}$=$\frac{mv^{2}}{r}$ ….(2)