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Question

Physics Question on Kinetic molecular theory of gases

The ratio of the specific heats of a gas is CpCv=1.66\frac{C_p}{C_v} = 1.66, then the gas may be

A

CO2CO_2

B

HeHe

C

H2H_2

D

NO2NO_2

Answer

HeHe

Explanation

Solution

Let 'nn' be the degree of freedom
γ=CpCv=(n2+1)R(n2)R=(1+2n)=1.66\gamma=\frac{C_{p}}{C_{v}}=\frac{\left(\frac{n}{2}+1\right) R}{\left(\frac{n}{2}\right) R}=\left(1+\frac{2}{n}\right)=1.66
=53=(1+23)=\frac{5}{3}=\left(1+\frac{2}{3}\right)
n=3\Rightarrow n=3
\Rightarrow gas must be monoatomic.