Question
Physics Question on Kinetic molecular theory of gases
The ratio of the specific heats of a gas is CvCp=1.66, then the gas may be
A
CO2
B
He
C
H2
D
NO2
Answer
He
Explanation
Solution
Let 'n' be the degree of freedom
γ=CvCp=(2n)R(2n+1)R=(1+n2)=1.66
=35=(1+32)
⇒n=3
⇒ gas must be monoatomic.