Question

The ratio of the radii of the nuclei $_{13}Al^{27}$ and $_{52}Te^{125}$ is

• A. $13:52$
• B. $27 : 125$
• C. $3 : 5$
• D. $14 : 73$

Answer 1

Answer: (C)

$3 : 5$

Answer 2

As $R \propto A^{1/3}$
$\Rightarrow \frac{R_{Al}}{R_{Te}} = \frac{(27)^{1/3}}{(125)^{1/3}}$
$\frac{R_{Al}}{R_{Te}} = \frac{3}{5}$