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Question

Physics Question on Nuclear physics

The ratio of the nuclear radii of elements with mass numbers 216216 and 125125 is

A

216:125216 : 125

B

216:125\sqrt {216} : \sqrt {125}

C

6:56 : 5

D

none of these

Answer

6:56 : 5

Explanation

Solution

Nuclear radius is proportional to A1/3A^{1 / 3},
where AA is the mass number of nucleus.
R=R0A1/3R=R_{0} A^{1 / 3}
where R0=1.2fmR_{0}=1.2\, fm
R1R2=R0(216)1/3R0(125)1/3=65\frac{R_{1}}{R_{2}}=\frac{R_{0}(216)^{1 / 3}}{R_{0}(125)^{1 / 3}}=\frac{6}{5}