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Question: The ratio of the maximum wavelength of the Lymen series in hydrogen spectrum to the maximum waveleng...

The ratio of the maximum wavelength of the Lymen series in hydrogen spectrum to the maximum wavelength in the Paschen series is –

A

3105\frac{3}{105}

B

615\frac{6}{15}

C

527\frac{52}{7}

D

7108\frac{7}{108}

Answer

7108\frac{7}{108}

Explanation

Solution

λ1λ2=(19−116)(11−14)=7108\frac{\lambda_{1}}{\lambda_{2}} = \frac{\left( \frac{1}{9} - \frac{1}{16} \right)}{\left( \frac{1}{1} - \frac{1}{4} \right)} = \frac{7}{108}