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Question: The ratio of the "e/m" (specific charge) values of a electron and an \(\alpha\) -particle is –...

The ratio of the "e/m" (specific charge) values of a electron and an α\alpha -particle is –

A

2 : 1

B

1 : 1

C

1 : 2

D

None of these

Answer

None of these

Explanation

Solution

(e/m)e((e/m))α=e/me2e/4×183me=36721\frac{(e/m)e}{\left( (e/m) \right)\alpha} = \frac{e/m_{e}}{2e/4 \times 183m_{e}} = \frac{3672}{1}