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Question: The ratio of specific heats of a gas is g. The change in internal energy of one mole of the gas, whe...

The ratio of specific heats of a gas is g. The change in internal energy of one mole of the gas, when the volume changes from V to 2V at constant pressure P is-

A

B

PV

C

PVγ−1\frac { \mathrm { PV } } { \gamma - 1 }

D

PVγ\frac { \mathrm { PV } } { \gamma }

Answer

PVγ−1\frac { \mathrm { PV } } { \gamma - 1 }

Explanation

Solution

DU = nCV.DT

= nRγ−1\frac { \mathrm { nR } } { \gamma - 1 } [DT]

P = const. PDV = nRDT

= =

ΔV=2 V−V=V\Delta \mathrm { V } = 2 \mathrm {~V} - \mathrm { V } = \mathrm { V }