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Question: The ratio of rotational KE of same amount of H<sub>2</sub> and CH<sub>4</sub> gas at same temperatur...

The ratio of rotational KE of same amount of H2 and CH4 gas at same temperature is (consider gas is ideal) –

A

2 : 3

B

8 : 1

C

16 : 3

D

None of these

Answer

16 : 3

Explanation

Solution

KEH2KECH4\frac{KE_{H_{2}}}{KE_{CH_{4}}} = 22m2RT32m16RT\frac{\frac{2}{2}\frac{m}{2}RT}{\frac{3}{2}\frac{m}{16}RT} = 23\frac{2}{3} × 162\frac{16}{2}