Question
Question: The ratio of rate of diffusion of gases A and B is \({\text{1:4}}\). If the ratio of their masses pr...
The ratio of rate of diffusion of gases A and B is 1:4. If the ratio of their masses present in the mixture is 2:3, what is the ratio of their mole fraction?
A) 81
B) 121
C) 161
D) 241
Solution
The change in number of molecules that diffuse per unit time is known as the rate of diffusion. We can apply Graham's law which states that the rate of diffusion of any gas is inversely proportional to the square root of the molar mass of gas.
Formula used: R2R1=M1M2
Complete step by step answer:
Graham’s law states that the rate of diffusion of any gas is inversely proportional to the square root of the molar mass of gas. Thus,
R2R1=M1M2
Where, R1 and R2 are the rates of diffusion,
M1 and M2 are the molar masses.
The ratio of rate of diffusion of gases A and B is 1:4. Thus,
41=M1M2
161=M1M2
M2M1=116 …… (1)
The ratio of molar masses of the gases present in the mixture is 2:3. Thus,
W2W1=32 …… (2)
The number of moles is the ratio of mass to the molar mass.
Thus, we can obtain the number of moles of gases by dividing equation (2) with equation (1). Thus,
n2n1=M2M1W2W1
n2n1=11632
n2n1=32×161
n2n1=241
Thus, the ratio of their mole fraction is 241.
Thus, the correct option is (D) 241.
Note: Rate of diffusion varies with different factors. Various factors that affect the rate of diffusion are as follows:
- Temperature: As the temperature increases, the movement of molecules increases. Thus, the rate of diffusion increases. Thus, the rate of diffusion is directly proportional to the temperature.
- Density of solvent: As the density of the solvent increases, the movement of molecules decreases. Thus, the rate of diffusion decreases. Thus, the rate of diffusion is inversely proportional to the density of solvent.