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Question

Physics Question on Moment Of Inertia

The ratio of radii of gyration of a circular ring and a circular disc, of the same mass and radius, about an axis passing through their centres and perpendicular to their planes are :

A

1:21: \sqrt 2

B

3 : 2

C

2 : 1

D

2:1\sqrt 2 :1

Answer

2:1\sqrt 2 :1

Explanation

Solution

Let M and R be mass and radius of the ring and the disc respectively. Then,
Moment of inertia of ring about an axis passing
through its centre and perpendicular to its plane is
Iring=MR2I_{ring} = MR^2
Moment of inertia of disc about the same axis is
Idisc=MR22I_{disc} = \frac{MR^2}{2}
As I=MK2I = MK^2 where k is the radius of gyration
Iring=MKring2=MR2\therefore I_{ring} = MK^2_{ring} = MR^2
or kring=Rk_{ring} = R
and Idisc=Mkdisc2=MR22I_{disc} = Mk^2_{disc} = \frac{MR^2}{2}
or kdisc=R2k_{disc} = \frac{R}{\sqrt 2}
kringkdisc=RR/2=21\therefore \frac{k_{ring}}{k_{disc}} = \frac{R}{R/ \sqrt 2} = \frac{\sqrt 2}{1}
kring:kdisc=2:1k_{ring} : k_{disc} = \sqrt 2 :1