Question

The ratio of paint and oil in Tank A is 3: 4, whereas in Tank B, the respective ratio is 4: 5 . Then, 96 liters of a mixture consisting of paint and oil in the ratio of 5: 1 is added to Tank A, such that the respective ratio in Tank A becomes exactly the reverse of that in Tank B. Find the amount (in liters) of the mixture from Tank B that is poured into Tank A such that the amount of paint and water in Tank A become equal.

• A. 306
• B. 296
• C. 284
• D. 316
• E. 324

Answer 1

Answer: (A)

306

Answer 2

Let the initial amount of mixture in Tank $A$ be $7x$.
The amount of paint and oil in $96$ litres of mixture is $80$ litres and $16$ litres.
Thus given,

$\frac{3x+80}{4x+16} =\frac{ 5}{4}$

or, $12x+320 = 20x+80$

or, $x = 30$

Total mixture in Tank $A$ = $210+96 = 306$

Thus, $306$ litres from Tank $B$ need to be poured into Tank $A$.

Hence, option A is the correct answer.