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Question

Physics Question on Atomic Spectra

The ratio of minimum wavelengths of Lyman and Balmer series will be

A

1.25

B

0.25

C

5

D

10

Answer

0.25

Explanation

Solution

For minimum wavelength,
λn2\lambda \propto n^{2}
λLyman λBalmer =(12)2\therefore \frac{\lambda_{\text {Lyman }}}{\lambda_{\text {Balmer }}}=\left(\frac{1}{2}\right)^{2}
λLλB=14=0.25\frac{\lambda_{L}}{\lambda_{B}}=\frac{1}{4}=0.25