Question

The ratio of minimum wavelength of Lyman and Balmer series will be-

• A. 1.25
• B. 0.25
• C. 5
• D. 10

Answer 1

Answer: (B)

0.25

Answer 2

For lyman;

$\frac{1}{\lambda_{\min}}$ = R$\left\lbrack \frac{1}{1} - \frac{1}{\infty} \right\rbrack$ = R

l_min = $\frac{1}{R}$

For Balmer;

$\frac{1}{\lambda_{\min}}$ = R$\left( \frac{1}{2^{2}} - \frac{1}{\infty} \right)$ =$\frac{R}{4}$

l_min = $\frac{4}{R}$

\$\frac{({\lambda Lyman}_{\min}}{({\lambda Balmer}_{\min}}$ = 0.25