Question
Question: The ratio of intensities of two waves is 1:16. What will be the ratio of their amplitudes? A. \(\d...
The ratio of intensities of two waves is 1:16. What will be the ratio of their amplitudes?
A. 1716
B. 161
C. 41
D. 21
Solution
We know that Intensity of a wave is directly proportional to the square of amplitude. That is, I∝a2. where I denotes the intensity of wave and a denotes the amplitude.
In equation form it can be written as I=ca2 where c is a constant. Since the ratio of intensity is given we can use this relation to find the ratio of amplitudes.
Complete step by step answer:
Let I1 be the intensity of the first wave and I1 be the intensity of the second wave.
Given, I1:I2=1:16
Intensity of a wave is directly proportional to the square of amplitude.
I∝a2
That is,
I=ca2 (1)
where c is a constant.
Let a1 be the amplitude of the first wave. Then using equation(1) the intensity of the first wave I1 can be written as ,
I1=ca12 (2)
Let a2 be the amplitude of the second wave Then using equation (1) intensity of second wave I2 can be written as ,
I2=ca22 (3)
Now let us divide equation (2) by (3). Then we get,
I2I1=ca22ca12
∴I2I1=a22a12
Now substitute the value of the ratio of intensities I2I1 in the above equation. Then we get,
161=a22a12
⇒a2a1=161
∴a2a1=41
Therefore, the ratio of amplitudes of the waves is 1:4.
So, the answer is option C
Note: The equation for finding intensity is given as I=2π2ρAυ2a2where ρ is the density of the medium, A is the area, υ is the frequency, a is the amplitude. While solving this question we assumed that 2π2ρAυ2 is a constant. Since change in any of these factors is not mentioned it is okay to consider all those values as constant. But when they are changing, we cannot consider them as constants.