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Question: The ratio of intensities of two waves is 1:16. What will be the ratio of their amplitudes? A. \(\d...

The ratio of intensities of two waves is 1:16. What will be the ratio of their amplitudes?
A. 1617\dfrac{{16}}{{17}}
B. 116\dfrac{1}{{16}}
C. 14\dfrac{1}{4}
D. 12\dfrac{1}{2}

Explanation

Solution

We know that Intensity of a wave is directly proportional to the square of amplitude. That is, Ia2I \propto {a^2}. where II denotes the intensity of wave and aa denotes the amplitude.
In equation form it can be written as I=ca2I = c{a^2} where c is a constant. Since the ratio of intensity is given we can use this relation to find the ratio of amplitudes.

Complete step by step answer:
Let I1{I_1} be the intensity of the first wave and I1{I_1} be the intensity of the second wave.
Given, I1:I2=1:16{I_1}:{I_2} = 1:16
Intensity of a wave is directly proportional to the square of amplitude.
Ia2I \propto {a^2}
That is,
I=ca2I = c{a^2} (1)
where c is a constant.
Let a1{a_1} be the amplitude of the first wave. Then using equation(1) the intensity of the first wave I1{I_1} can be written as ,
I1=ca12{I_1} = c{a_1}^2 (2)
Let a2{a_2} be the amplitude of the second wave Then using equation (1) intensity of second wave I2{I_2} can be written as ,
I2=ca22{I_2} = c{a_2}^2 (3)
Now let us divide equation (2) by (3). Then we get,
I1I2=ca12ca22\dfrac{{{I_1}}}{{{I_2}}} = \dfrac{{c{a_1}^2}}{{c{a_2}^2}}
I1I2=a12a22\therefore \dfrac{{{I_1}}}{{{I_2}}} = \dfrac{{{a_1}^2}}{{{a_2}^2}}
Now substitute the value of the ratio of intensities I1I2\dfrac{{{I_1}}}{{{I_2}}} in the above equation. Then we get,
116=a12a22\dfrac{1}{{16}} = \dfrac{{{a_1}^2}}{{{a_2}^2}}
a1a2=116\Rightarrow \dfrac{{{a_1}}}{{{a_2}}} = \sqrt {\dfrac{1}{{16}}}
a1a2=14\therefore \dfrac{{{a_1}}}{{{a_2}}} = \dfrac{1}{4}
Therefore, the ratio of amplitudes of the waves is 1:4.
So, the answer is option C

Note: The equation for finding intensity is given as I=2π2ρAυ2a2I = 2{\pi ^2}\rho A{\upsilon ^2}{a^2}where ρ\rho is the density of the medium, AA is the area, υ\upsilon is the frequency, aa is the amplitude. While solving this question we assumed that 2π2ρAυ22{\pi ^2}\rho A{\upsilon ^2} is a constant. Since change in any of these factors is not mentioned it is okay to consider all those values as constant. But when they are changing, we cannot consider them as constants.