Question

The ratio of area of orbit of first excited state of electron to the area of ground level, for hydrogen atom, will be –

• A. 16 : 1
• B. 4 : 1
• C. 8 : 1
• D. 2 : 1

Answer 1

Answer: (A)

16 : 1

Answer 2

A µ r², r µ n², A µ n⁴

$\frac{A_{1}}{A_{2}}$ = $\frac{n_{1}^{4}}{n_{2}^{4}}$= 16