Question

The ratio mass of oxygen and nitrogen of a particular gaseous mixture is $1 : 4$ The ratio of number of their molecule is

• A. $1 : 4$
• B. $7 : 32$
• C. $1 : 8$
• D. $3 : 16$

Answer 1

Answer: (B)

$7 : 32$

Answer 2

Let the mass of $O _{2}= x$ Mass of $N _{2}=4 x$ Number of moles of $O _{2}=\frac{ x }{32}$ Number of moles of $N _{2}=\frac{4 x }{28}=\frac{x}{7}$ $\therefore$ Ratio $=\frac{x}{32}: \frac{x}{7}=7: 32$