Question

The ratio activity of an element becomes 1/64^th of its original value in 60 sec. Then the half life period is-

• A. 5 sec
• B. 10 sec
• C. 20 sec
• D. 30 sec

Answer 1

Answer: (B)

10 sec

Answer 2

A.P = $\frac { 1 } { 64 }$ = (n = 6) t = n T_1/2 ̃ T_1/2 = $\frac { \mathrm { t } } { \mathrm { n } }$ = $\frac { 60 } { 6 }$

= 10 sec