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Question: The rate of the reaction: \(CH_{3}COOC_{2}H_{5} + NaOH \rightarrow CH_{3}COONa + C_{2}H_{5}OH\) is ...

The rate of the reaction:

CH3COOC2H5+NaOH→CH3COONa+C2H5OHCH_{3}COOC_{2}H_{5} + NaOH \rightarrow CH_{3}COONa + C_{2}H_{5}OH is given by the equation,

Rate = k[CH3COOC2H5][NaOH]k\lbrack CH_{3}COOC_{2}H_{5}\rbrack\lbrack NaOH\rbrack

If concentration is expressed in mol/L the units of k are

A

mol−2L2s−1mol^{- 2}L^{2}s^{- 1}

B

molL−1s−1molL^{- 1}s^{- 1}

C

Lmol−1s−1Lmol^{- 1}s^{- 1}

D

s−1s^{- 1}

Answer

Lmol−1s−1Lmol^{- 1}s^{- 1}

Explanation

Solution

For a second order reaction dxdt=k[A]2\frac{dx}{dt} = k\lbrack A\rbrack^{2}

conc.time=k[conc.]2\frac{conc.}{time} = k\lbrack conc.\rbrack^{2}

molL−1s=kmolL−1×molL−1\frac{molL^{- 1}}{s} = kmolL^{- 1} \times molL^{- 1}

k=Lmol−1s−1k = Lmol^{- 1}s^{- 1}