Question

The rate of reaction between $A$ and $B$ increases by a factor of 100, when the concentration of $A$ is increased 10 folds. The order of reaction with respect to $A$ is.

• A. 10
• B. 1
• C. 4
• D. 2

Answer 1

Answer: (D)

2

Answer 2

$r = K\lbrack A\rbrack^{n},100r = K\lbrack 10A\rbrack^{n}$

Thus $\frac{1}{100} = \left( \frac{1}{10} \right)^{n}$or n = 2