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Question: The rate of radiation of a black body at 0°C is EJ/sec. The rate of radiation of this black body at ...

The rate of radiation of a black body at 0°C is EJ/sec. The rate of radiation of this black body at 273C273 ^ { \circ } \mathrm { C } will be

A

16E16 E

B

8E8 E

C

4E4 E

D

EE

Answer

16E16 E

Explanation

Solution

E1E2=(T1T2)4EE2=(273+0273+273)4\frac { E _ { 1 } } { E _ { 2 } } = \left( \frac { T _ { 1 } } { T _ { 2 } } \right) ^ { 4 } \Rightarrow \frac { E } { E _ { 2 } } = \left( \frac { 273 + 0 } { 273 + 273 } \right) ^ { 4 } E2=16E\Rightarrow E _ { 2 } = 16 E .