Question

The rate of radiation of a black body at 0ŗC is E joule per sec. Then the rate of radiation of this black body at 273ŗC will be -

• A. 16 E
• B. 8 E
• C. 4 E
• D. E

Answer 1

Answer: (A)

16 E

Answer 2

$\frac{E_{2}}{E_{1}}$ = $\left( \frac{T_{2}}{T_{1}} \right)^{4}$ = $\left( \frac{546}{273} \right)^{4}$ = $\frac{16}{1}$ \ E₂ = 16E₁