Question
Question: The rate of emission of radiation of a black body of temperature 27<sup>0</sup>C is E<sub>1</sub>. I...
The rate of emission of radiation of a black body of temperature 270C is E1. If its temperature is increased to 3270C, the rate of emission of radiation is E2. The relation between E1& E2 is –
A
E2 = 24 E1
B
E2 = 16 E1
C
E2 = 8 E1
D
E2 = 4 E1
Answer
E2 = 16 E1
Explanation
Solution
T1 = 27 + 273 = 300 K
T2 = 327 + 273 = 600 K
By Stefan's law
E2E1= T24T14 = (600300)4
\ E2 = 16 E1