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Question: The rate of emission of radiation of a black body at \({273^ \circ }C\) is \(E\), then what will be ...

The rate of emission of radiation of a black body at 273C{273^ \circ }C is EE, then what will be the rate of emission of radiation of the body at 0C{0^ \circ }C?
A. E16\dfrac{E}{{16}}
B. E4\dfrac{E}{4}
C. E8\dfrac{E}{8}
D. 00

Explanation

Solution

Hint- Stefan's law gives us the expression for total power radiated per unit surface area of a black body.
According to this law, the total power radiated per unit surface area of a black body is directly proportional to the fourth power of temperature. In mathematical form this law can be written as,
ET4E \propto {T^4}
Here, TT is the temperature of the black body.

Step by step solution:
Stefan's law gives us the expression for total power radiated per unit surface area of a black body.
According to this law, the total power radiated per unit surface area of a black body is directly proportional to the fourth power of temperature. In mathematical form this law can be written as,
ET4E \propto {T^4}
Or
E=σT4E = \sigma {T^4}
Where, σ\sigma is the Stefan’s constant and TT is the temperature.
Given,
Temperature,
T1=273C =273+273K =556K  {T_1} = {273^ \circ }C \\\ = 273 + 273\,K \\\ = 556\,K \\\
Let the rate of emission of radiation of black body at 273C{273^ \circ }C be denoted as E1{E_1}.
Therefore, using Stefan’s law, we can write,
E1=σT14{E_1} = \sigma {T_1}^4 ……. (1)
Temperature,
T2=0C =0+273K =273K  {T_2} = {0^ \circ }C \\\ = 0 + 273\,K \\\ = 273\,K \\\
Let the rate of emission of radiation of black body at 0C{0^ \circ }C be denoted as E2{E_2}.
Therefore, using Stefan’s law, we can write,
E2=σT24{E_2} = \sigma {T_2}^4 …… (2)
Divide equation (1) by (2). Then, we get

E1E2=T14T24 E1E2=(T1T2)4  \dfrac{{{E_1}}}{{{E_2}}} = \dfrac{{{T_1}^4}}{{{T_2}^4}} \\\ \dfrac{{{E_1}}}{{{E_2}}} = {\left( {\dfrac{{{T_1}}}{{{T_2}}}} \right)^4} \\\

Now substitute the given values. Then, we get

E1E2=(556273)4 =(2)4 =16  \dfrac{{{E_1}}}{{{E_2}}} = {\left( {\dfrac{{556}}{{273}}} \right)^4} \\\ = {\left( 2 \right)^4} \\\ = 16 \\\

That is,
E2=E116{E_2} = \dfrac{{{E_1}}}{{16}}

Hence the correct answer is option A.

Note: Remember to convert the temperatures given in C^ \circ C into the corresponding temperature in kelvin.
Formula to remember
Stefan’s law, E=σT4E = \sigma {T^4}
Where, EE is the total power radiated per unit surface area of a black body and TT is the temperature of black body.