Question
Question: The rate of emission of radiation of a black body at \({273^ \circ }C\) is \(E\), then what will be ...
The rate of emission of radiation of a black body at 273∘C is E, then what will be the rate of emission of radiation of the body at 0∘C?
A. 16E
B. 4E
C. 8E
D. 0
Solution
Hint- Stefan's law gives us the expression for total power radiated per unit surface area of a black body.
According to this law, the total power radiated per unit surface area of a black body is directly proportional to the fourth power of temperature. In mathematical form this law can be written as,
E∝T4
Here, T is the temperature of the black body.
Step by step solution:
Stefan's law gives us the expression for total power radiated per unit surface area of a black body.
According to this law, the total power radiated per unit surface area of a black body is directly proportional to the fourth power of temperature. In mathematical form this law can be written as,
E∝T4
Or
E=σT4
Where, σ is the Stefan’s constant and T is the temperature.
Given,
Temperature,
T1=273∘C =273+273K =556K
Let the rate of emission of radiation of black body at 273∘C be denoted as E1.
Therefore, using Stefan’s law, we can write,
E1=σT14 ……. (1)
Temperature,
T2=0∘C =0+273K =273K
Let the rate of emission of radiation of black body at 0∘C be denoted as E2.
Therefore, using Stefan’s law, we can write,
E2=σT24 …… (2)
Divide equation (1) by (2). Then, we get
Now substitute the given values. Then, we get
E2E1=(273556)4 =(2)4 =16That is,
E2=16E1
Hence the correct answer is option A.
Note: Remember to convert the temperatures given in ∘C into the corresponding temperature in kelvin.
Formula to remember
Stefan’s law, E=σT4
Where, E is the total power radiated per unit surface area of a black body and T is the temperature of black body.