Question

The rate of elementary reaction, $A \rightarrow B$, increases by a 100 when the concentration of A is increased ten folds. The order of the reaction with respect to A is

• A. 1
• B. 10
• C. 2
• D. 100

Answer 1

Answer: (C)

2

Answer 2

$R = k\lbrack A\rbrack^{n}$; Also, 100R = $k\lbrack 10A\rbrack^{n}$; $\frac{1}{100} = \left\lbrack \frac{1}{10} \right\rbrack^{n}$; $\therefore n = 2$