Solveeit Logo

Question

Chemistry Question on States of matter

The rate of diffusion of methane is twice that of X. The molecular mass of X is

A

16

B

32

C

80

D

64

Answer

64

Explanation

Solution

rmethaner_{methane} 2 a (say), rxr_x - a
rmethanerX=MXMmethane\frac{r_{methane}}{r_X}= \sqrt{\frac{M_X}{M_{methane}}}
2aa=Mx16\frac{2a}{a} = \sqrt{\frac{M_x}{16}}
Mx16\frac{M_x}{16} = 4 or MxM_x = 64