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Question: The rate of diffusion of methane at a given temperature is twice that of gas X. The molecular weight...

The rate of diffusion of methane at a given temperature is twice that of gas X. The molecular weight of X is

A

64.0

B

32.0

C

4.0

D

8.0

Answer

64.0

Explanation

Solution

rCH4rX=MXMCH42=MX16MX=64\frac { r _ { C H _ { 4 } } } { r _ { X } } = \sqrt { \frac { M _ { X } } { M _ { C H _ { 4 } } } } \Rightarrow 2 = \sqrt { \frac { M _ { X } } { 16 } } \Rightarrow M _ { X } = 64.