Question

The rate of diffusion of a gas having molecular weight just double of nitrogen gas is 56 ml $s ^ { - 1 }$ . The rate of diffusion of nitrogen will be

• A. 79.19 ml $s ^ { - 1 }$
• B. 112.0 ml $s ^ { - 1 }$
• C. 56 ml $s ^ { - 1 }$
• D. 90.0 ml $s ^ { - 1 }$

Answer 1

Answer: (A)

79.19 ml $s ^ { - 1 }$

Answer 2

$\frac { r _ { X } } { r _ { N _ { 2 } } } = \sqrt { \frac { M _ { N _ { 2 } } } { M _ { X } } } = \sqrt { \frac { 28 } { 56 } } = \sqrt { \frac { 1 } { 2 } }$;

$r _ { N _ { 2 } } = 56 \sqrt { 2 } = 79.19 \mathrm {~ms} ^ { - 1 }$