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Question

Mathematics Question on Surface Areas and Volumes

The rate of change of volume of a sphere with respect to its surface area when the radius is 4 cm is:

A

(A) 4 cm3/cm2

B

(B) 6 cm3/cm2

C

(C) 2 cm3/cm2

D

(D) 8 cm3/cm2

Answer

(C) 2 cm3/cm2

Explanation

Solution

Explanation:

We know that, volume of sphere V=43πr3Surface area of sphere S=4πr2, where r is the radius of the sphere.So, rate of change of volume of sphere,⇒dVdt=ddt(43πr3)=43×3×πr2drdt⇒dVdt=4πr2drdt ----(1)Rate of change of surface area of sphere,⇒dSdt=ddt(4πr2)=4π×2×rdrdt⇒dSdt=8πrdrdt ----(2)From equation (1) and equation (2),⇒dVdS=dVdtdSdt=4πr2drdt8πrdrdt⇒4r8=2(∵r=4 cm)Therefore, the rate of change of volume of a sphere with respect to its surface area is 2 cm3/cm2.Hence, the correct option is (C).