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Question

Mathematics Question on Applications of Derivatives

The rate of change of the area of a circle with respect to its radius rr at r=6cmr = 6 cm is

A

10π10\pi

B

12π12\pi

C

8π8\pi

D

11π11\pi

Answer

12π12\pi

Explanation

Solution

The correct answer is B:12π12\pi
The area of a circle (A)(A) with radius (r)(r) is given by,
A=πr2A=πr^2
Therefore, the rate of change of the area with respect to its radius rr is
dAdr=ddr(πr2)=2πr\frac{dA}{dr}=\frac{d}{dr}(πr^2)=2πr
∴When r=6cmr = 6 cm,
dAdr=2π×6=12πcm2/s\frac{dA}{dr}=2π\times6=12πcm^2/s
Hence, the required rate of change of the area of a circle is 12πcm2/s12π cm^2 /s. The correct answer is B.