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Question

Chemistry Question on Chemical Kinetics

The rate of a reaction quadruples when the temperature changes from 300300 to 310K310\, K. The activation energy of this reaction is : (Assume activation energy and pre-exponential factor are independent of temperature; ln2=0.693;R=8.314Jln\, 2 = 0.693; R=8.314 \,J mol1K1mol^{-1} \, K^{-1})

A

107.2kJmol1107.2 \, kJ \, mol^{-1}

B

53.6kJmol153.6 \, kJ \, mol^{-1}

C

26.8kJmol126.8 \, kJ \, mol^{-1}

D

214.4kJmol1214.4 \, kJ \, mol^{-1}

Answer

107.2kJmol1107.2 \, kJ \, mol^{-1}

Explanation

Solution

4=e^{\frac{Ea}{R}\left\\{\frac{1}{300}-\frac{1}{310}\right\\}} In\left(4\right)=\frac{Ea}{R}\left\\{\frac{10}{300\times310}\right\\} Ea=0.693×2×8.314×300×31010Ea=\frac{0.693\times 2\times 8.314\times 300\times 310}{10} =107165.79J=107.165KJ=107165.79 \,J =107.165\, KJ