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Question: The rate of a reaction is doubled for every \(10^{o}\) rise in temperature. The increase in reaction...

The rate of a reaction is doubled for every 10o10^{o} rise in temperature. The increase in reaction rate as a result of temperature rise from 10o10^{o} to 100o100^{o} is.

A

112

B

512

C

400

D

614

Answer

512

Explanation

Solution

kt+10Kt=rt+10rt=2\frac{k_{t} + 10}{K_{t}} = \frac{r_{t} + 10}{r_{t}} = 2

For an increase of temperature to 90oC90^{o}C i.e. 9 times, the rate increases by 292^{9} times i.e. 512.