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Question: The rate of a first order reaction is \(1.5 \times {10^{ - 2}}mol{L^{ - 1}}{\min ^{ - 1}}\) at \(0.5...

The rate of a first order reaction is 1.5×102molL1min11.5 \times {10^{ - 2}}mol{L^{ - 1}}{\min ^{ - 1}} at 0.5M0.5M concentration of the reactant.
The half life of the reaction is:
A. 0.383min0.383\min
B. 23.1min23.1\min
C. 8.73min8.73\min
D. 7.53min7.53\min

Explanation

Solution

A first-order reaction is one in which the rate of the reaction is linearly proportional to the concentration of only one reactant. In other terms, a first-order reaction is a chemical reaction whose rate is determined by changes in the concentration of one reactant. As a result, the order of these reactions is 1.
Formula Used:
Rate of reaction =k[A] = k[A]
k=k = Rate constant of first order reaction
A=A = Concentration of first order reaction
Half life of first order reaction is given by:
t0.5=0.693k{t_{0.5}} = \dfrac{{0.693}}{k}

Complete answer:
Rate of reaction =1.5×102 = 1.5 \times {10^{ - 2}}
A=0.5MA = 0.5M
To find: Half life of the reaction
First, we need to find the rate constant of the reaction,
Using the above given formula,
k=1.5×1020.5k = \dfrac{{1.5 \times {{10}^{ - 2}}}}{{0.5}}
k=3×102k = 3 \times {10^{ - 2}}
For Half – life of a reaction,
t0.5=0.693k{t_{0.5}} = \dfrac{{0.693}}{k}
Substituting the value of kk in the above equation,
t0.5=0.6933×102{t_{0.5}} = \dfrac{{0.693}}{{3 \times {{10}^{ - 2}}}}
t0.5=23.1min{t_{0.5}} = 23.1\min
Hence, the half life of the reaction is 23.1min23.1\min .
Hence, the correct option is B. 23.1min23.1\min .

Note:
The half-life of a chemical reaction is the amount of time it takes for the reactant concentration to reach half of its initial value. A unimolecular reaction is another name for a first-order reaction. As we know rate depends only on one reactant, other reactants may be present, but they will all be zero-order because their concentrations have no effect on the rate.