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Question: The rate law of the reaction \(2N_{2}O_{5} \rightarrow 4NO_{2} + O_{2}\) is....

The rate law of the reaction 2N2O5→4NO2+O22N_{2}O_{5} \rightarrow 4NO_{2} + O_{2} is.

A

r=K[N2O5]r = K\lbrack N_{2}O_{5}\rbrack

B

r=K[N2O5]2r = K\lbrack N_{2}O_{5}\rbrack^{2}

C

r=K[N2O5]0r = K\lbrack N_{2}O_{5}\rbrack^{0}

D

r=K[NO2]4[O2]r = K\lbrack NO_{2}\rbrack^{4}\lbrack O_{2}\rbrack

Answer

r=K[N2O5]r = K\lbrack N_{2}O_{5}\rbrack

Explanation

Solution

Rate law for the reaction 2N2O5→4NO2+O22N_{2}O_{5} \rightarrow 4NO_{2} + O_{2}

is r=k[N2O5]r = k\lbrack N_{2}O_{5}\rbrack first order reaction.