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Question: The rate law for the reaction \(RCl + NaOH(aq) \rightarrow ROH + NaCl\) is given by Rate \(= K_{1}...

The rate law for the reaction

RCl+NaOH(aq)→ROH+NaClRCl + NaOH(aq) \rightarrow ROH + NaCl is given by Rate

=K1[RCl]= K_{1}\lbrack RCl\rbrack. The rate of the reaction will be.

A

Doubled on doubling the concentration of sodium

hydroxide

B

Halved on reducing the concentration of alkyl halide to one half

C

Decreased on increasing the temperature of the

reaction

D

Unaffected by increasing the temperature of the

Reaction

Answer

Halved on reducing the concentration of alkyl halide to one half

Explanation

Solution

R=K[RCl]R = K\lbrack RCl\rbrack, if [RCl] =1/2, then rate = R/2.